If we list all the natural numbers below 10 that are multiples of 3
or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
using System;
namespace Dela.Mono.Examples
{
public class HelloWorld
{
public static void Main(string[] args)
{
int limit = 1000;
int counter = 0;
int sum = 0;
while (counter < limit)
{
if (counter % 3 == 0 || counter % 5 == 0)
{
sum = sum + counter;
}
counter++;
}
Console.WriteLine("Enter the limit " + sum);
}
}
}